80=40t-5t^2

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Solution for 80=40t-5t^2 equation: 



80=40t-5t^2

We move all terms to the left:

80-(40t-5t^2)=0

We get rid of parentheses

5t^2-40t+80=0

a = 5; b = -40; c = +80;
Δ = b2-4ac
Δ = -402-4·5·80
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{40}{10}=4$

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